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I'm currently beginning to program with Java. I tried to code the sequence in the title as an output in Java, but I'm stuck! I'm experimenting with the for function, any help is welcomed ;)
Started by El Toro on
, 7 posts
by 7 people.
Answer Snippets (Read the full thread at stackoverflow):
)); System.out.print(Integer.toString(i, 2).replaceAll("[01]", "$0 "));
Why two loops?
(converted from C#, pardon any in another language (Ruby):
4.times {|n| print 10**(n+1)}
System.out.println("1 0 1 0 0 1 0....
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Hi all.
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Started by ALFrance on
, 20 posts
by 8 people.
Answer Snippets (Read the full thread at gtplanet):
I might be totally Muscle Car, 205 ? in 0....
Thanks to MrFitswell for his Christmas Gift ;-)
Now available with Toyota FT-86 Concept II '11 - in 0 / 0 / 0
Silky black
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Dam....and I thought I wouldn't reach 1,000 at one point. Just goes to show when u have a forum with great topics and most importantly great people around, it's never a dull place to be.
Big what up to all those who make BZ the place it is....u know who...
Started by ILUVAdrianaLima on
, 20 posts
by 12 people.
Answer Snippets (Read the full thread at bellazon):
Starts ye cause we ROC D, WE ROCK THE CASB It's about time lazy Btw, just realised you joined 2 days.
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Ask your Facebook Friends
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I'm doing a task in a subject were fib 0 is defined to = 1. But that can't be right? Fib 0 is 0?
Program with fib 0 = 1; spits out fib 4 = 5 Program with fib 0 = 0; spits out fib 3 = 3
What is correct?
Started by misterfixit on
, 7 posts
by 7 people.
Answer Snippets (Read the full thread at stackoverflow):
Fib 0 = 0 fib 1 = 1
That is the seed value ....
The nth element:
F(n) = ( f^n - (1-f)^n ) / sqrt(5), where f = (1 + sqrt(5)) / 2 [the golden ratio]
For n = 0 it is clearly 0:
F(0) = (1 - 1) / sqrt(5) = 0.
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Edit: To clarify, the problem is how to round a number to the nearest integer. i.e. 0.5 should round to 1 and 2.5 shoud round to 3.
Consider the following code:
<html><head></head><body style="font-family:courier"> <script>...
Started by eft on
, 5 posts
by 5 people.
Answer Snippets (Read the full thread at stackoverflow):
Instead of toFixed(0) use Math.ceil() or Math.floor() , depending guess that your intent with usin....
If f < 0 or f > 20, throw a RangeError is what you are looking for.
2.
Is undefined, this step produces the value 0).
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The MSDN documentation mentions that double type includes negative zero. However, both -1.0 / double.PositiveInfinity and -double.Epsilon / 2 appear to return normal 0 (and compare equal to it). How can I get -0?
Started by Alexey Romanov on
, 6 posts
by 6 people.
Answer Snippets (Read the full thread at stackoverflow):
There is more); Console.WriteLine(d); }
Output:
0 0 -Infinity Infinity
Take note that -0 and 0 both look the same does....
Also, -0 should always compare equal to +0.
Archive this value is by setting it directly.
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Lets say we have an array of char pointers
char* array[] = { "abc", "def" };
Now what should be put in the end ?
char* array[] = { "abc", "def", '\0' };
or
char* array[] = { "abc", "def", "\0" };
Though, both works. We only have to put the condition to...
Answer Snippets (Read the full thread at stackoverflow):
To the compound literal (char [2]){ 0, 0 } NULL , '\0' and 0 are all null pointer constants, so they'll allWell, technically '\0' is a character while "\0" is a string, so if you're checking for the null....
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Today I came a cross an article by Eric Lippert where he was trying to clear the myth between the operators precedence and the order of evaluation. At the end there were two code snippets that got me confused, here is the first snippet:
int[] arr = {0...
Started by Galilyou on
, 6 posts
by 6 people.
Answer Snippets (Read the full thread at stackoverflow):
// Now evaluate the RHS int rhs = data[i] + 5; //... .
Now i=2.
Data[1].
Retrieve the value of arr[(result of #2)] which is arr[0], which (per #3 = i; i++; // We're going to assign to data[index], i.e.
The value of arr[0] to 1.
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Is it necessary to add cellspacing="0" cellpadding="0" in
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