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What's an elegant way to unify X,Y with (1,2), (1,-2), (-1,2), (-1,-2), (2,1), (2,-1) , (-2,1), (-2,-1)?
Doing it this way seems error prone and tedious:
foo(1,2). foo(1,-2). foo(-1,-2). ... ... ...
And this way seems too expensive:
foo(X,Y) :- L = [1...
Started by Absolute0 on
, 4 posts
by 4 people.
Answer Snippets (Read the full thread at stackoverflow):
Foo(X, Y) :- foo(-....
Foo(2, 1).
Foo(1, 2).
Foo(X,Y):- foo0(X,Y); foo0(Y,X).
A further development on what was commented:
generate_pairs_foo(X,Y) :- L = [1,-1,2,-2], member(X,L]), member(Y,[2,-2]).
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What's the most most ruby-like way of converting from an Array like [:one, 1, :two, 2] to a Hash like {:one => 1, :two => 2} ?
Started by Bob Aman on
, 3 posts
by 3 people.
Answer Snippets (Read the full thread at stackoverflow):
Here's how I would do it:
Hash[*array]
Hash[*[:one, 1, :two, 2]] #=> {:one => 1, :two => 2}.
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How does:
1 + 2 + ... + N-1 + N + N + N-1 + ... + 2 + 1 N+1 + N+1 + ... + N+1 + N+1
equal N(N + 1)? Shouldn't it be 4N + 4 or 4(N + 1)?
Started by Brandon on
, 5 posts
by 5 people.
Answer Snippets (Read the full thread at stackoverflow):
Thus row 1 + row 2 = n*(n+1)
Read the part about the early years of Carl represent....
There are n columns.
Each column of the first 2 rows adds up to n+1.
1 + row 2 = row 3?
in this case, look at the columns.
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Ask your Facebook Friends
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In mathematics the identity (1 + sqrt(2))^2 = 3 + 2*sqrt(2) holds true. But in floating point (IEEE 754, using single precision i.e. 32 bits) calculations it's not the case, as sqrt(2) doesn't have an exact representation in binary.
So does using a approximated...
Started by Naximus on
, 18 posts
by 18 people.
Answer Snippets (Read the full thread at stackoverflow):
Generally I use [(1 + sqrt(2))^2] - [3 + 2*sqrt(2)] < 0.00001 to test equality
In double....
When comparing floating point purposes.
Multiplying by 2, etc.
To that same number on both sides: Adding 1 vs.
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How do I detect programmatically in which ring (-1, 0, 1, 2, 3) I am running?
Started by Andrew J. Brehm on
, 4 posts
by 4 people.
Answer Snippets (Read the full thread at stackoverflow):
(SEH, Windows, kernel mode)
bool ring_lower_0 = false....
The easiest way is, to just run the (x86) command and catch the corresponding error .
Unless you're a device driver, you'll always be running in Ring 3 (for systems that have "rings", per se) .
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Anyone knows?
Started by AhYap on
, 12 posts
by 10 people.
Answer Snippets (Read the full thread at photomalaysia):
Online warranty 1+2 http://www.canon.com.my/personal/web...yinfo_personal yeah, should be 1+2
http://www.canon.com.my/personal/web...yinfo_personal Please takeIs 1+1 does....
To be paid to them like Harvey Norman.
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1) long to wide question:
I have a dataset with 3 columns: person, event, frequency. If the frequency is zero, the row is not in the table. Is there a simple way using basic R functions or libraries to convert this table to wide format, with one row per...
Started by Patrick McCann on
, 3 posts
by 3 people.
Answer Snippets (Read the full thread at stackoverflow):
Data[filteredRows,]
For the first part of your question, you can either use... .
Re: the first part, you can filter out the rows with Frequency == 0 by
filteredRows <- data$Frequency != 0 ## restrict ourselves to looking at the data where Frequency != 0 .
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Hi,
I got the following regex that almost does the work but does not exclude zero ...How to do that?
^(\d|\d{1,9}|1\d{1,9}|20\d{8}|213\d{7}|2146\d{6}|21473\d{5}|214747\d{4}|2147482\d{3}|21474835\d{2}|214748364[0-7])$
Also can anybody explain a bit how...
Started by Tanmoy on
, 4 posts
by 4 people.
Answer Snippets (Read the full thread at stackoverflow):
In essence....
The regex you pasted works:
The most important thing to remember is that 2**31 - 1 = 2147483647 (a number;= 2**31 - 1
In addition to the other answers, your regex doesn't work (besides allowing 0 with 10 digits).
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What's 1 + 2 + 6 + 1 + 5 + 1 + 2 + 3 + 6 + 7 + 1 (but it's not 35)? It's a puzzle and it's doing my head in.
Started by Someone on
, 8 posts
by 8 people.
Answer Snippets (Read the full thread at yahoo):
12615123671 ? Source....
Are you sure all of the signs are plus signs? I saw a riddle similar to this years ago, and one of the signs was actually a division sign, but looked so close to a plus sign, that you didn't notice it unless you looked very carefully .
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With CGContextSetLineWidth(context, 1) the width is almost alwayas at least 2 pixels instead 1
QQCandleStickLayer.m
-(id)init { self = [super init]; if(self != nil) { self.delegate = self; self.opaque = NO; } return self; } - (void)drawLayer:(CALayer*...
Started by freennnn on
, 3 posts
by 3 people.
Answer Snippets (Read the full thread at stackoverflow):
Sticking it to the pixel grids makes appears to be 1 pixel wide at 50% opacity on both sides, making it a 2 pixel wide line....
The line width is indeed 1 pixel wide, but 0.5 pixel wide on one side and 0.5 pixel wide on the other side.
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