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I want to calculate the average of a set of angles, which represents source bearing (0 to 360 deg) - (similar to wind-direction) I know it has been discussed before (several times). The accepted answer was Compute unit vectors from the angles and take...
Started by on , 12 posts by 12 people.  
Equivalent, but more robust algorithm (and simpler): divide angles into 2 groups, [0-180) and [180-360 the angles into 2 groups: [0-180) and [180-360) for angle in newAngles: if angle < 180 any real consensus....
On Wed, 4 Mar 2009 04:41:01 +0000 (UTC), "Ben " <benlawr2000@yahoo.com Hi, I am new to MATLAB. Can anyone give me hints on how to solve 2 nonlinear equations. The angles are unknown. Basically, i have this equation: r2*cos(theta_2) - r1*cos(theta...
Started by on , 4 posts by 2 people.  
Answer Snippets (Read the full thread at omgili):
When I tried solving the four equations: x4-x3 = p of your 1st equation....
X3+q*y3 = (r4^2-r3^2-p^2-q^2)/2 Solving for, say, y3 in terms of x3 in this and substituting the range from -pi to +pi or from 0 to 2*pi.
How do you use the sine rule to find TWO unknown angles or sides? The Question is as follows; x/sin(30) = 4-x/sin(45) Prove that x = 4(root 2 -1) Please help ASAP!!
Started by on , 5 posts by 5 people.  
Answer Snippets (Read the full thread at yahoo):
) =(4-x)/(1/root2) giving 2x=root2(4-x) and solving gives x=4root2/(2+root2) which you rationalizesin30 = 1/2 and sin45 = 1/√2 I am assuming you mean x/sin30 = (4 - x)/sin45 => 2x = (4 - x)√2 => 2x + x√2 = 4√....
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I have learned a lot of formulas for converting trigonometric values, but when I looked up sin(pi/10) I got the exact answer (1/4)(√5 +1). I tried to arive at this using formulas, but I couldn't. How is this found? What other angles can be found exactly...
Started by on , 9 posts by 4 people.  
For small angles sinx is very formulas (sin(a)^2 = (1-cos 2a)/2 ) Half and double angle formulas (derived from the above two formulas) Sum to product formulas....
Not sure where or how you got the exact answer, but it is not right .
So, I got this idea. I wanted to see if it is possible, without using an iterative solution, to determine the angle and bearing required to launch a projectile with a known gravitational acceleration and velocity and hit a target with a known acceleration...
Started by on , 5 posts by 2 people.  
During my simplification of this problem from 3 dimensions to 2 dimensions, I have actually failed....
In this axis, thus the value for acceleration is 0, and thus the (1/2)*a*(t^2) term gets dropped this, I am realizing a horrible mistake.
On Thu, 7 May 2009 11:47:01 +0000 (UTC), "Andrew Mackenzie" <#macac#001#@students.unisa.edu.au I am trying to find the value of t, when phi = 60? or pi/3 radians. syms t x = 8 + 2 * cos(pi*t); alpha = atan(8/x); beta = acos(sqrt(x^2 + 64) / 40)...
Started by on , 7 posts by 4 people.  
Answer Snippets (Read the full thread at omgili):
In mathematical, not programatical ....
Typed exactly there, in case), and I do not get what you got EDU phi = pi - atan(8/(2*cos(pi*t) + 8)) - acos(1/20*(1/4*(2*cos(pi*t) + 8)^2 + 16)^(1/2)) EDU EDU ans = 1.0000 - 1.1377i.
On Wed, 24 Jun 2009 02:03:21 -0700 (PDT), Archimedes Plutonium <plutonium.archimedes@gmail.com Alright, here is another part of Calculus that the limit is unable to perform, but where the AP-Reals is at home and comfortable in solving. On page ...
Started by on , 13 posts by 4 people.  
Answer Snippets (Read the full thread at omgili):
So, (1) you have no logical head to even think with (2) you need to learn if the function 1/x^2 of Strang's page 86 can be rigged to have a break of 10^(-)500 as x approaches 0 a Parallel Postulate for you would....
To consider your questions.
On Wed, 24 Jun 2009 11:33:21 -0500, "Mackly" <invalid@invalid.com "Archimedes Plutonium" <plutonium.archimedes@gmail.comnews:9ce460f2-007a-43c3-bcb9-b1128d74211a@z34g2000vbl.googlegroups.com... <snip crap WRONG. What is the value of the...
Started by on , 12 posts by 4 people.  
Answer Snippets (Read the full thread at omgili):
Now I wonder if the function 1/x^2 of Strang's page 86 can be rigged to have a break of 10^(-)500 then you cannot have a Parallel....
So, (1) you have no logical head to even think with (2) you.
And then expect me to consider your questions.
Finding the angle between two vectors is not hard using the cosine rule. However, because I am programming for a platform with very limited resources, I would like to avoid calculations such as sqrt and arccos. Even simple divide's should be limited as...
Started by on , 7 posts by 7 people.  
Where length of V1 L1 = sqrt(x1^2 + y1^2), and length of V2 L2 = sqrt(x2^2 + y2^2*y2))); Have you tried a CORDIC algorithm? It's a general framework for solving polar ↔ rectangular problems with only add/subtract/....
I have a vector consisting of a point, speed and direction. We will call this vector R. And another vector that only consists of a point and a speed. No direction. We will call this one T. Now, what I am trying to do is to find the shortest intersection...
Started by on , 5 posts by 5 people.  
Some equation solving you end up with (4) I) a = sum(p-q)/(s 2 -sum(d 2 )) II) b = 2*sum(d*(p-q))/(s 2 the direction vector e , write it like this (2) e = (p-q)/t + d Now you don't need the time t point directly....
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