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I have a ruby hash:
VALS = { :one => "One", :two => "Two" }
and an Array:
array2 = ["hello", "world", "One"]
Question: How can I populate a new array1 so that it only pulls in any values in array2 that match exactly the values in VALS?
For example...
Started by Eric on
, 5 posts
by 4 people.
Answer Snippets (Read the full thread at stackoverflow):
The contents as sets:
array1 = VALS.values & array2 print array1
Output:
One
Here's an option:
hash = { :one.
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How can iterate with a while loop until array1 is empty.
So far based on several conditions I'm pushing elements from array1 to array2. But I want to iterate array1 until everything from array1 is in array2.
something like:
// or while everything from...
Started by Josh Darrow on
, 3 posts
by 3 people.
Answer Snippets (Read the full thread at stackoverflow):
Count() would work:
while(count(array1)){ if(somecondition1) array_push(array2,"Test"); elseif,"Test"); elseif(somecondition2) array_push(array2,"Test"); } until (count(array1) == 0)
Here's a test I did expanding upon your....
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Say I have 2 of the same arrays, and in the beginning I make array2 = array1, then I change properties in an element in array1, but it also changes the same element in array2
int[] array1,array2;
array1 = new int[2]; array2 = new int[2];
array1[0] = 1...
Answer Snippets (Read the full thread at msdn):
And assigns it to array1
array1 = new int[5];
when you assign from array1 = array2 this is really saying
the reference array1 = the reference to array2
so your reassigning the memory location;i ++)
{
array....
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Im curious to know if php has a function that allows me to connect 2 arrays together and replace values from array1 with values of array2 if the values from array2 already exist. see example
array1('value1','value2','value3',); array2('value4','value2...
Started by numerical25 on
, 6 posts
by 6 people.
Answer Snippets (Read the full thread at stackoverflow):
The function you're looking for is called array_merge
array array_merge ( array $array1 [, array $array2 for that, but this will work:
$array3 = array_keys(array_flip($array1) + array_flip($array2))
Set::merge.
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In Objective-C, if array1 is copied onto array2 using mutableCopy, and suppose the code is done in main(), who is responsible for releasing the objects contained in the array? Is it main() or array2?
Started by huggie on
, 5 posts
by 5 people.
Answer Snippets (Read the full thread at stackoverflow):
When you create array2 via -mutableCopy , you get an NSMutableArray ....
From the NSArray documentation are retained by the NSArray array1 .
Or array2?
Both array1 and array2 are responsible for releasing the objects.
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I have two string arrays "Array1[size]" and "Array2[size]". They both have the same size. I would like to write a function which contains this two arrays but I am having problems in the way that I am declaring them.
I am declaring it like this: void Thefunction...
Started by jualin on
, 4 posts
by 4 people.
Answer Snippets (Read the full thread at stackoverflow):
You can do:
template <std::size_t size> void TheFunction(string (&Array1)[size], string (&Array2)[size....
Like this:
void TheFunction(string Array1[], string Array2[], int size automatically.
To take arrays of strings.
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I have the following?
$array1 = array(); $array2 = array($Id, $Name, $Count); array_push($array1, $array2);
I want to sort array1 on the $count?
sort() and ksort() don't do what i require?
Any ideas?
Thanks
Edit:
I am inputing an Id number, name text ...
Started by Rigobert Song on
, 3 posts
by 3 people.
Answer Snippets (Read the full thread at stackoverflow):
Echo "<pre>"; print_r($array1); echo "</pre>"; $array2 = order_by($array1, 'Count'); echo] == $b[2]) { return 0; } return ($a[2] < $b[2]) ? -1 : 1; } uasort($array1, 'sort_callback');
I'm['$field_name']);....
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Code:
/* * code.c */ #include <stdio.h> void printArray(int iXArray, int iSize); int main() { int array1[] = {7, 9, 3, 18}; int *array2[] = {array1 + 0, array1 + 1, array1 + 2, array1 + 3}; printArray(array2, 4); return 0; } // This should print...
Started by Pieter on
, 6 posts
by 6 people.
Answer Snippets (Read the full thread at stackoverflow):
Void printArray(int *iXArray[], int iSize); int main() { int array1[] = {7, 9, 3, 18}; int *array2[] = {&array1[0], &array1[1], &array1[2], &array1[3]}; printArray(array2, 4); return 0; } // This should....
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I am writting a Perl script to create pie graph using GD::Graph::pie with these arrays:
@Array1 = ("A", "B", "C", "D"); $array2 = [ ['upto 100 values'], ['upto 100 values'], ['upto 100 values'], ['upto 100 values'] ];
As per my understanding to get this...
Started by Octopus on
, 5 posts
by 5 people.
Answer Snippets (Read the full thread at stackoverflow):
You almost certainly mean:
my @graph_data = (\@Array1, $array2); # you want the first element of each....
Less directly:
my @graph_data = (\Array1, $@array2); my @graph_data1 = (\Array1[0], $@array2[0]);
looks mad.
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OK, I am trying to get a sub array from an existing array and I'm just not sure how to do it. In my example I have a very large array, but I want to create an array from the last 5 elements of the array.
An example of what I am talking about would be:...
Started by John on
, 9 posts
by 9 people.
Answer Snippets (Read the full thread at stackoverflow):
For this:
"such that array1[96] and array2[0] would be pointing to the same location."
you can do}; int* array2 = &array1[95];
In C++ you can use an int pointer as an int array, so getting the array2 to start at item....
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