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<==== [b_d] (((( {Next Lounge X 10 Mini / X 10 MiniPro } )))) [b_d] ====>
Quote: : Quote: : "SELAMAT HARI NATAL 2011 DAN TAHUN BARU 2012"
Wish you all the best Quote: : Quote: : WELCOME TO ANDROID WORLD with SE X10Mini / SE X10MiniPro Quote: : Quote...
Started by Zedcool on
, 19 posts
by 1 people.
Answer Snippets (Read the full thread at kaskus):
TUTORIAL MODULE OVERCLOCK by agan://www.zid*du.com/download/1....
System/etc/permissions/
set permission ke 644
begini:
Read Write Execute
[X]----[X] [ ]
[X]----[ ] [ ]
[X]----[ ] [ ]
gambarnya:
Spoiler for kayak gini :
thx..
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Im trying to model the EBNF expression
("declare" "namespace" ";")* ("declare" "variable" ";")*
I have built up the yacc (Im using MPPG) grammar, which seems to represent this, but it fails to match my test expression.
The test case i'm trying to match...
Started by Sprotty on
, 3 posts
by 3 people.
Answer Snippets (Read the full thread at stackoverflow):
The parser gets to the last PrologHeader , and it has to decide whether... .
It seems that you need a 2-token lookahead in this situation .
It's been a long time since I've used anything yacc-like, but here are a couple of suggestions that may or may not help .
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Derby doesn't support this syntax:
UPDATE x SET (col1, col2, ...) = ( SELECT a,b,... FROM y ... )
(see this bug ). Does anyone have a workaround other than creating a loop in Java which does the select and sends N updates back?
[EDIT] Note that I have...
Started by Aaron Digulla on
, 3 posts
by 3 people.
Answer Snippets (Read the full thread at stackoverflow):
Have you tried:
UPDATE x SET (col1)= ( SELECT a FROM y where y.fkfield = x.pkidfield), (col21)= ( SELECT b FROM y where y.fkfield = x.pkidfield), ).
Siad but I'm also a MSSQL person.
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Ask your Facebook Friends
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(More package/component install fun for me -- thanks everyone for all your help to date).
I am getting the error listed as the title, in Delphi 2007. Package A is my package of frame-based "viewer panels." Package B is a package containing a couple of...
Started by Jamo on
, 4 posts
by 4 people.
Answer Snippets (Read the full thread at stackoverflow):
There's a couple of ways around this....
Unit X is clearly being linked into both packages.
X in Package B, and have Package A use Package B (which is a more compact form of the firstIt could also be related to this question .
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The value of x in the expression 1/(x-a) +1/(x-b) = 0 is? I know the answer's supposed to be (a+b)/2
*You're not doing my hw for me. This isn't hw. I'm reviewing for a college entrance test (not in the US), and these are the list of questions I could ...
Started by Junko on
, 6 posts
by 6 people.
Answer Snippets (Read the full thread at yahoo):
(....
x-a) + 1/(x-b) = 0
1/(x-a) = -1/(x-b)
x-b = -x + a
2x = a + b
x = (a+b)/2 1/(x-a) + 1/(x-b) = 0
Multiply by (x-a)(x-b).
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I was looking for a way to do a BITOR() with an Oracle database and came across a suggestion to just use BITAND() instead, replacing BITOR(a,b) with a + b - BITAND(a,b).
I tested it by hand a few times and verified it seems to work for all binary numbers...
Started by CaptainAwesomePants on
, 5 posts
by 5 people.
Answer Snippets (Read the full thread at stackoverflow):
Lt;stdio.h> int main(){ unsigned int a=0xC , b=0xA ; printf("%x %x %x %x\n",a, b, a|b, a&b); printf("%x %x %x %x\n",a+b, a-(a&b), a-(a&b)+b, a+b-(a&....
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New home of the Twipz and Sky duo!
Oh. And Chester. That Handsome Cat over there~
Welcome to Scribble Sketch! A place to hangout and get art. O u O
Head on down to the rules section and you can find out how to get some art. ♥
Dont forget to us~!! (butnoreallydoit...
Started by Twipz on
, 15 posts
by 9 people.
Answer Snippets (Read the full thread at gaiaonline):
> u.
Z
> u < b
Hello There~ Nice to Meet ya!
Im excited to get back into the drawing mood.
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Alright, let's say I have these two tables:
items with columns id, stuff item_properties with columns item_id, prop_id Now I want to execute a query like
SELECT stuff FROM items WHERE EXISTS(SELECT * FROM item_properties WHERE prop_id = 123 AND item_id...
Started by KiNgMaR on
, 5 posts
by 5 people.
Answer Snippets (Read the full thread at stackoverflow):
If I understood your problem correctly, ....
SELECT stuff FROM Items as i INNER JOIN item_properties as ip ON i.id = ip.item_id WHERE ip.prop_id IN (123, 456) AND ip.prop_id NOT IN (789, 101)
It's NOT TESTED, but that the kind of thing I tend to do a lot .
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; A;
*desperate*
If it makes you wish to sell it to me more... I'm buying to keep those pretty horns. crying Not sell them. <3
Started by Saint Ciel on
, 15 posts
by 2 people.
Answer Snippets (Read the full thread at gaiaonline):
Smile Loud as a Whisper
X_X I know right?
And it's odd that quite a few people here.
You need.
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ご回答大変有難うございます。
はい。
：
片方がφになればfは単射という事になります。
片方ともφにならないなら,∀a∈Aに対してb∈Bが唯一つ決めれた事になるのでこの時のfも単射となります。
はい。
AもBも可算の場合はAもBもN(:自然数全体)に対等だから
∃f:A→N:全単射, ∃g:N→B:全単射だから
gf:A→B:単射が採れお仕舞い。
Aが非可算でBが可算の場合は#A=アレフ1,#B=アレフ0で
AはR(:実数全体)に対等だから∃f:R→A:全単射,
BはN(:自然数全体...
Started by kyokoyoshida123@gmail.com on
, 4 posts
by 2 people.
Answer Snippets (Read the full thread at omgili):
A×B の部分集合 C....
A の部分集合 A' と B の部分集合 B' との間の
全単射は, 積集合 A×B のある部分集合 C のことだと
考えられます.
そうですが,
これは意味不明.
そんでは役に立ちません.
A が実数全体との間に全単射がある集合で,
B が自然数全体との間に全単射がある集合であれば,
確かに正しいですが, そんな遣り方で, 任意の集合
同士の場合を証明するには日が暮れます.
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