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As part of a program I'm writing, I need to solve a cubic equation exactly (rather than using a numerical root finder): a*x**3 + b*x**2 + c*x + d = 0. I'm trying to use the equations from here . However, consider the following code (this is Python but...
Started by on , 4 posts by 4 people.  
You can trim down the cubic solver....
I also solved the equation using Wolfram of here: roots3and4.c This contains quadratic, cubic, and quartic solvers which return all solutions.
I've looked at the Wikipedia article and your program.
Roots of a cubic equation? 'The roots of cubic equation 2x^3 + 3x + 4 = 0 are a, b, and c. Find the cubic equation, with integer coefficients, having roots ab, bc, and ac.' I'm so stuck! Thanks in advance.
Started by on , 1 posts by 1 people.  
Answer Snippets (Read the full thread at yahoo):
Hi all, I need to write an algorithm which finds the real roots to a cubic equation. I am applying a cubic equation of state to a chemical engineering problem, and a specific cubic equation needs to be solved thousands of times over the course of one ...
Started by on , 2 posts by 2 people.  
Answer Snippets (Read the full thread at sosmath):
ANy....
I am applying a cubic equation of state to a chemical engineering problem, and a specific cubic equation roots.
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What is the best way to approximate a cubic Bezier curve? Ideally I would want a function y(x) which would give the exact y value for any given x, but this would involve solving a cubic equation for every x value, which is too slow for my needs, and there...
Started by on , 3 posts by 3 people.  
If you're talking about Bezier from http://en.wikipedia.org/wiki/Cubic_equation#Summary , it would appear that there might be problems plane curves....
Just solve the cubic.
Solving the cubic equation by Cardano's method.
Can someone help me to find solution on how to calculate cubic root of the negative number using python? >>> math.pow(-3, float(1)/3) nan it does not work. Cubic root of the negative number is negative number. Any solutions?
Started by on , 10 posts by 10 people.  
cubic_root(nr): if nr<0: return -math.pow(-nr, float(1)/3) else: return math.pow(nr, float(1)/3] Taking the earlier answers and making it into a one-liner: import math def cubic_root(x): return libm.cbrt.argtypes = [c_double] libm.cbrt....
R question: Looking for the fastest way to NUMERICALLY solve a bunch of arbitrary cubics known to have real coeffs and three real roots. The polyroot function in R is reported to use Jenkins-Traub's algorithm 419 for complex polynomials, but for real ...
Started by on , 8 posts by 8 people.  
Google will give you than using the cubic solver in the GSL package (as suggested by knguyen above) is a matter.
Algorithm that exploits the structure of each equation using toric geometries.
How do you solve: i know the solutions cant be real, but how would you solve this algebraically not graphically or any other means. thank you
Started by on , 4 posts by 2 people.  
Living in their pools.
Here is some information: http://en.wikipedia.org/wiki/Cubic_function#Roots_of_a_cubic_function The above cubic has 3 real distinct roots, as its discriminant is positive.
The method I am describing today was given by Girolamo Cardano-an Italian mathematician,who first showed this method in his book Ars Magna. Let us attempt to solve the general cubic equation: Later,I will show you how this method is used for some cubic...
Started by on , 3 posts by 2 people.  
Explanation,you can look at this page: Method of Solving General Cubic Equations.
Solve in positive integers the cubic x^3–(x+1)^2=2001
Started by on , 5 posts by 5 people.  
It is ....
The solution (obviously) is 13 but you know how Dirty n Untidy n Ugly the cubic equations bricks without clay." Hi; He probably graphed the equation and eyeballed the root as 13 developed for solving a general cubic.
I am unsure as what this question means: Consider the cubic population model: dN/dt = cN(N-k)(1-N) where c>0 and 0<k<1 If the the initial populations is N_0 describe without proof the future of the population, distinguish the various cases on...
Started by on , 3 posts by 2 people.  
If N< 0.
We can write the equation as dN/dt= (-1)(N- 0)(N- k)(N- 1).
Happens between those values.
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