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Right now in Flash CS3 and up (using Actionscript 3) if you have the same instance that is used in multiple keyframes in a layer, and you decide to assign or change the instance name later, you would have to go to each keyframe and set the instance name...
Started by Boon on
, 7 posts
by 6 people.
Answer Snippets (Read the full thread at stackoverflow):
Write down your new instance ....
Else 'finding and replacing instance names" For "Symbol" Name [your instance's symbol] Ensure that Live Edit is UNchecked.
Is serial, you just assign the name in first of that.
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I'm trying to create a basic template to display the selected instance's field values, along with their names. Think of it as just a standard output of the values of that instance in table format, with the field name (verbose_name specifically if specified...
Started by Wayne Koorts on
, 7 posts
by 7 people.
Answer Snippets (Read the full thread at stackoverflow):
Model._meta.get_all_field_names() will give you all the model's field names, then you can use model._meta.get_field() to work your way to the verbose name, and getattr() to get the value GetModelData(form, fields): """ Extract data....
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I cannot figure out what my object instance names are because of how I am generating them and adding them to the stage...
var circles:Array = new Array() //Declare array for displaying multiple objects function spawn(evt:MouseEvent):void { //MouseEvent...
Started by Structure on
, 5 posts
by 5 people.
Answer Snippets (Read the full thread at stackoverflow):
It would go something like this:
for each(var myCircle:circle in circles) { myCircle.gotoAndStop(2); }
UPDATE: According to your comment, there are many options (different arrays, etc...) but as far as I can tell from what you've said, I would create ... .
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So I successfully added a movie clip from the library using addChild(), but now I want to access some movieclips that were in that dynamically added movieclip.
I've used standard dot notation and also getChildByName passing it the instance names.
What...
Started by Justin Lee on
, 5 posts
by 5 people.
Answer Snippets (Read the full thread at stackoverflow):
So if you have MovieClip with instance name 'a' and inside you have a MovieClip with instance name 'b' then you can simply with the....
Then you can access a particular child movieclip if it has an instance name.
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Any idea if there is a way to make the following code to work
class Test(object): def __init__(self, var): self.var = var def changeme(self): self = Test(3) t = Test(1) assert t.var == 1 t.changeme() assert t.var == 3
is something like the following safe...
Started by vinilios on
, 4 posts
by 4 people.
Answer Snippets (Read the full thread at stackoverflow):
To do what you want you'd need to have access to a name outside the class, which you could = Test(2) myclass.changeme() print myclass....
Python names aren't locked to values, they are always relative to their scope or namespace.
Of changeme().
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If I create a new instance of a class with IB I can't send messages to it because I don't know its name. I have asked several people and they always say 'you just use files owner' but that doesn't answer my question. What is the instances name?
Started by Christopher Farnell on
, 4 posts
by 4 people.
Answer Snippets (Read the full thread at stackoverflow):
For example, if you create an instance of MyObject, you'll be able to reference it by creating MyViewController @....
In order to refer to an object in a nib by name, you must have an instance variable with that name outlet.
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How can I obtain the position of a instance whose name is stored in an variable? If there is a instance whose name I don't know, but the instance's name is store in an variable x. How can I obtain its position?
Started by john on
, 6 posts
by 5 people.
Answer Snippets (Read the full thread at stackoverflow):
Let's say the input text the display objects on stage instance names if they //were dynamically created var myMovieClip;
Thanks a lot, Sthg, and Allan....
EDIT: If you have a input text, where users would type the instance name.
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I'm writing a client for a group of RESTful services. The body of the REST calls have the same XML structure, given parameters. There are several dozen calls, and I will not be implementing all of them. As such, I want to make them easy to specify and...
Started by Ian Stevens on
, 3 posts
by 3 people.
Answer Snippets (Read the full thread at stackoverflow):
, **kwargs: bracketit(m(*args, **kwargs))) method = build_method(m) setattr(C, m.__name__, method) setattr(C, m.__name__, method)
when run in your test code produces:
<bound method C.new_method.
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All the examples I look at for reflection show creating a new instance of an unknown implementation, and casting that implementation to it's interface. The issue with this is that now you can't call any new methods (only overrides) on the implementing...
Started by hal10001 on
, 6 posts
by 6 people.
Answer Snippets (Read the full thread at stackoverflow):
You....
So what you are trying to do is not possible .
You canIf you knew the Class of ImplementationType you could create an instance of it.
The String representation of the Class name to cast your reflected instance to a known type.
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I am doing something like this:
class Class(object): def __init__(self): self.var=#new instance name string#
How do I make the __ init __ method of my instance to use the instance name string for 'c'? Say in case:
c=Class()
I want c.var equal to 'c'.
...
Started by Alex on
, 11 posts
by 10 people.
Answer Snippets (Read the full thread at stackoverflow):
This is a scope issue, you can't do way using the names....
What should be given for the following code afterwards is this object bound to the name of the instance.
Not even be a name, or there could be multiple such names.
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