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I want to achieve the following: Have a AxBxC matrix (where A,B,C are integers). Access that matrix not as matrix[a, b, c] but as matrix[(a, b), c], this is, I have two variables, var1 = (x, y) and var2 = z and want access my matrix as matrix[var1, var...
Started by on , 3 posts by 3 people.  
If var1 = (x,y) , and var2 = z , you can use matrix[var1][var2] I think you can simply subclass the NumPy matrix type, with a new class of your own; and overload the __getitem__() nethod to accept.
Suppose I have an AxBxC matrix X and a BxD matrix Y . Is there a non-loop method by which I can multiply each of the C AxB matrices with Y ?
Started by on , 7 posts by 7 people.  
You....
Big matrix Z = reshape(reshape(permute(X, [2 1 3]), [A B*C]), [B A*C])' * Y; %'# split into third) = ZZ(7:8, :); So you can see it only requires one matrix multiplication, but you have to reshape the matrix before and after.
Suppose I have a integer matrix which represents who has emailed whom and how many times. For social network analysis I'd like to make a simple undirected graph. So I need to convert the matrix to binary matrix and later into a list of tuples. My question...
Started by on , 3 posts by 3 people.  
You can do the following: >>>.
[EDIT] Cudos to speciousfool : If x is your matrix then scipy.sign(x) gives you the binary matrix.
Apply the scipy.sign function to every cell in the matrix.
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I want to model a purification of the Petri Network. And i was given the suggestion to use a matrix which is allocated dynamically. After thinking about the problem i came up with a different approach like so: A static matrix of n transitions and p locations...
Started by on , 3 posts by 3 people.  
A dynamically allocated matrix is better: can be resized to suit the input dimensions you pay only.
I need some help in converting a 2X2 matrix to a 4X4 matrix in the following manner: A = [2 6; 8 4] should become: B = [2 2 6 6; 2 2 6 6; 8 8 4 4; 8 8 4 4] How would I do this?
Started by on , 7 posts by 7 people.  
Solution: A = [2 6; 8 4]; B = A([1 1 2 2], [1 1 2 2]); A = [2 6; 8 4]; % arbitrary 2x2 input matrix B.
I'm trying to inverse a matrix with version Boost boost_1_37_0 and MTL mtl4-alpha-1-r6418. I can't seem to locate the matrix inversion code. I've googled for examples and they seem to reference lu.h that seems to be missing in the above release(s). Any...
Started by on , 4 posts by 4 people.  
Rather, it....
Says you need lu.h, somehow: How do I invert a matrix? The first question you should ask yourself is whether you want to really compute the inverse of a matrix or if you really want to solve a linear the matrix inverse.
Hello, Unfortunately I haven't much experience in C++ and I'm trying to progress myself in C++. Firstly,I defined array of arrays so that I formed an 3x3 matrix: array< array< double >^ >^ input = gcnew array< array< double >^ >...
Started by on , 5 posts by 5 people.  
There is not built....
Look at Simple 3x3 matrix inverse code (C++) .
There are no functions in C++ to make matrix operations, you'll need to find some library to do a wrapper function around an available Fortran or C or C++ implementation.
I have a 3d matrix ( n-by-m-by-t ) in MATLAB representing n-by-m measurements in a grid over a period of time. I would like to have a 2d matrix, where the spatial information is gone and only n*m measurements over time t are left (ie: n*m-by-t ) How can...
Started by on , 3 posts by 3 people.  
This is equivalent to the form B=reshape(A,[],1);.
You need the command reshape : Say your initial matrix is (just for me to get some data): a=rand = A(:); to create a vector directly from a matrix.
If I do positionVector*worldMatrix the position is transformed into world space. But what happens if I do it the other way around (worldMatrix*positionVector) in terms of 3d space? I noticed the result is different to the first one. I already googled ...
Started by on , 5 posts by 5 people.  
In terms of 3D it, but it is beyond my understanding ... .
Incidentally, doing the one is the same as doing the other after transposing the matrix.
In vector*matrix.
In matrix*vector, your vector will be interpreted as a column vector.
Given a large sparse matrix (say 10k+ by 1M+) I need to find a subset, not necessarily continuous, of the rows and columns that form a dense matrix (all non-zero elements). I want this sub matrix to be as large as possible (not the largest sum, but the...
Started by on , 4 posts by 4 people.  
You don....
Is your intent to write your own? Maybe the 1D approach run of column indexes that I could .
D sub-matrix with the highest sum of brightness values, where "Brightness" was measured matrix libraries might have ways to handle it.
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