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Is there a more elegant solution to convert an ' Arraylist ' into a ' Arraylist<Type> '?
Current code:
ArrayList productsArrayList=getProductsList(); ArrayList<ProductListBean> productList = new ArrayList<ProductListBean>(); for (Object...
Started by Amoeba on
, 4 posts
by 4 people.
Answer Snippets (Read the full thread at stackoverflow):
The example given which....
The way you).
Hence, ArrayList<ProductListBean> and ArrayList are the same thing, and casting (as in Matthew's answers) will work.
The collection is simply an ArrayList since the type info has been erased.
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How to move one Arraylist data to another arraylist. I have tried for many option but the output is in the form of array not arraylist
Started by balaweblog on
, 8 posts
by 8 people.
Answer Snippets (Read the full thread at stackoverflow):
ArrayList l1=new ArrayList(); l1.Add("1"); l1.Add("2"); ArrayList l2=new ArrayList(l1);
ArrayList model = new ArrayList(); ArrayList copy = new ArrayList(model);
?
Use....
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I'm storing data in a HashMap with (key: String, value: ArrayList). The part I'm having trouble with declares a new ArrayList "current," searches the HashMap for the String "dictCode," and if found sets current as the returned value ArrayList.
ArrayList...
Started by cksubs on
, 6 posts
by 6 people.
Answer Snippets (Read the full thread at stackoverflow):
ArrayList current = dictMap.get(dictCode and:
test.put("test", arraylistone); ArrayList current = new ArrayList(); current = (ArrayList) test.get current = new....
new HashMap<String, ArrayList>(); ...
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I am using the toString method of ArrayList to store ArrayList data into a String. My question is, how do I go the other way? Is there an existing method that will parse the data in the String back into an ArrayList?
Answer Snippets (Read the full thread at stackoverflow):
A, b, c]" public List parse(String s) { List output = new ArrayList(); String listString = s.substring/questions/456367/reverse-parse-the-output-of-arrays-tostringint
It depends on what you're storing in the ArrayList(0, s.length....
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I have an array that is initialised like:
Element[] array = {new Element(1),new Element(2),new Element(3)};
I would like to convert this array into an object of the ArrayList class.
ArrayList<Element> arraylist = ???;
I am sure I have done this ...
Started by Ron Tuffin on
, 6 posts
by 6 people.
Answer Snippets (Read the full thread at stackoverflow):
The list returnednew ArrayList<Element>(....
Otherwise you'll get an UnsupportedOperationException.
arraylist = Arrays.asList(array);
The simplest answer is to do:
Element[] array = new Element it in a new ArrayList().
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I'm creating a TableModel which will have a fixed number of columns, but the number of rows will be changing (mostly, increasing as function of time). Which would be better approach to store the data,
ArrayList[] columns = new ArrayList[numberOfColumns...
Started by Joonas Pulakka on
, 5 posts
by 5 people.
Answer Snippets (Read the full thread at stackoverflow):
And you need a fixes length whereas ArrayList are flexible....
How about using a single ArrayList itself_OF_COLUMNS+column); }
In this case, each ArrayList object is a cell in a table.
You to query the number, type and name of columns .
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How do I get an array slice of an ArrayList in Java? Specifically I want to do something like this:
ArrayList<Integer> inputA = input.subList(0, input.size()/2); // where 'input' is a prepouplated ArrayList<Integer>
So I expected this to work...
Started by B T on
, 5 posts
by 5 people.
Answer Snippets (Read the full thread at stackoverflow):
So I feel why it wouldn't....
EDIT : Actually, I think you can take that List and use it to instantiate a new ArrayList using one of the ArrayList constructors .
Consecutive element and appending it to a new ArrayList.
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In theory, is it easier to add new elements to an ArrayList or to a LinkedList ?
Started by Johanna on
, 5 posts
by 5 people.
Answer Snippets (Read the full thread at stackoverflow):
Do you mean, ArrayList will be better, and....
LinkedList 's time never changes.
They are the same: Collections.add
It depends: If the backing array is full, ArrayList will have to create a new one before it can add another element.
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We have:
class A{} class B extends A{} class C extends B{} class D extends C{}
we can define Lists like:
List<? super B> lsb1 = new ArrayList<Object>(); //List<? super B> lsb2 = new ArrayList<Integer>();//Integer, we expect this...
Started by wzawirski on
, 3 posts
by 3 people.
Answer Snippets (Read the full thread at stackoverflow):
String[] x = new String[10]; Object[] x2 = x; x2[0] = 123; // not a String, compiles, but crashes.
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How do i print the element "e" in arraylist "list" out?
ArrayList<Dog> list = new ArrayList<Dog>(); Dog e = new Dog(); list.add(e); System.out.println(list);
Started by noname on
, 5 posts
by 5 people.
Answer Snippets (Read the full thread at stackoverflow):
String[] args) { List<Dog> list = new ArrayList<Dog>(); Dog e = new Dog("Tommy"); list.add(e); list.add(new Dog("tiger")); System.out.println(list); for(Dog d:list) { System.out.println(d.
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