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What is the best way to return the whole number part of a decimal (in c#)? (This has to work for very large numbers that may not fit into an int).
GetIntPart(343564564.4342) >> 343564564 GetIntPart(-323489.32) >> -323489 GetIntPart(324) >...
Started by Yaakov Ellis on
, 6 posts
by 6 people.
Answer Snippets (Read the full thread at stackoverflow):
I would do:
Math.Floor....
Edit: Truncate is definitely it every time.
A DECIMAL or a DOUBLE.
You can't get the "int" part of a decimal this:
Math.Truncate(number)
and return the value as...
By the way guys, (int)Decimal.MaxValue will overflow.
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Hi Guys,
Can any of you provide me with the correct part numbers for a Golf Mk2 1991 3dr rear seat belt part numbers please.
Thank you.
Chris
Started by Chrisrpal on
, 13 posts
by 4 people.
Answer Snippets (Read the full thread at com):
I thought part.
And mathed them so they looked the same and work perfect apart from one being twisted .
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Does anyone know of an elegant way to get the decimal part of a number only? In particular I am looking to get the exact number of places after the decimal point so that the number can be formatted appropriately. I was wondering if there is away to do...
Started by MT on
, 4 posts
by 4 people.
Answer Snippets (Read the full thread at stackoverflow):
In particular the number according to the current....
The fourth integer, after masking out the sign) to indicate the number of decimal places, but you should be aware that it's not necessarily the number of significant decimal places.
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If I have a credit number that is an int and I just want to display the last 4 numbers with a * on the left, how would I do this in C#?
For example, 4838382023831234 would shown as *1234
Started by Xaisoft on
, 7 posts
by 7 people.
Answer Snippets (Read the full thread at stackoverflow):
Of 10,000 which will return the last four digits of the int
If the number is stored as a string = "*" + ccNumber.Substring(ccNumber.Length - 4);
A credit card number will overflow an int32 and just like phone numbers = "*"+s.Substring....
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How can we extract the decimal part of a floating point number and to store the decimal part and the integer part into seperate two integer variables?
Started by Binu on
, 9 posts
by 9 people.
Answer Snippets (Read the full thread at stackoverflow):
To do what you want with the fractional part, just keep multiplying it by 10 until....
I don't see how you could put the decimal part into an integer unless you knew how many digits the whole part from the fractional part.
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Hello!
Is it possible to always have the 'Part' section to start at an odd page number? So that if the part one section extends to page two, then part two automatically moves to page three. I'm using Lyx to create the Latex file.
EDIT: Just discovered...
Started by Orjanp on
, 3 posts
by 3 people.
Answer Snippets (Read the full thread at stackoverflow):
Chapters start on the next option does not take care of this problem, then the following surely will:
\let\originalpart=\part \def\part{\cleardoublepage\originalpart....
Part, for default, starts at an odd page and occupies the whole page.
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I have several large files, each of which I want to chunk/split it in to predefined number of parts.
Is there an efficient way to do it in Unix (e.g. via awk/sed/perl)?
Also each file can have varied number of lines.
File1.txt 20,300,055 lines File2.txt...
Started by neversaint on
, 4 posts
by 4 people.
Answer Snippets (Read the full thread at stackoverflow):
You may need to find the number of parts to be splited it too first.
I found this.
If you just want to split each file into files of a fixed number of lines or bytes, you can use the split command.
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Hi,
I'm trying to write a regex to validate part or model numbers.
These can contain letters, numbers, '-', '/' and spaces. They must contain at least 1 number and be between 4 and 20 characters long.
Here are some examples of the strings I want to match...
Started by carok on
, 6 posts
by 6 people.
Answer Snippets (Read the full thread at stackoverflow):
IMO it's better to make one regex per model number format and
then combine them matching the APL821....
APL8215 because the rules are pragmatic enough to match This is my model APL as a valid part number before into the same output.
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I've a regex that matches comma separated numbers with an optional two digit decimal part in a given multiline text.
/(?<=\s|^)\d{1,3}(,\d{3})*(\.\d{2})?(?=\s|$)/m
It matches strings like 1, 12, 12.34, 12,345.67 etc successfully. How can I modify it...
Started by Amarghosh on
, 3 posts
by 3 people.
Answer Snippets (Read the full thread at stackoverflow):
.99 fds 12.34 dfs 12,345.67 er 666.666 er 999,999,999,999,999.99"; $number_regex = "/(?<=\s|^)(?:\d{1,3}(?:,\d{3})*(?:\.\d\d)?|\.\d\d)(?=\s|$)/"; if(preg_match_all($number_regex, $text, $matches.
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What is a good algorithm to determine the necessary fraction needed to add/sub to the number in order to round it to the nearest integer without using the inbuilt ceiling or floor funcitons?
Edit: Looking for a mathematical number trick to figure out ...
Started by kunjaan on
, 5 posts
by 5 people.
Answer Snippets (Read the full thread at stackoverflow):
Once you have the fractional part of the number
OR
Divide the number by 0.5, if its....
It is interesting to think about, though.
Mod the number with one to get the decimal part, if its >0.5, round up, else round down.
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