|
I'm using an image as the submit button for a search form, i.e.:
<input id="search" type="image" alt="Search" src="/images/searchButton.png" name=""/>
This has an unfortunate side effect in Chrome and Firefox--the parameters &x=0&y=0 appear on the...
Started by Jack7890 on
, 5 posts
by 5 people.
Answer Snippets (Read the full thread at stackoverflow):
Type="image"> , you could use a <button> element:
<button type="submit" style="border: 0.
|
|
Variable x is int with possible values: -1, 0, 1, 2, 3 . Which expression will be faster (in CPU ticks):
1. (x < 0) 2. (x == -1)
Language: C/C++, but I suppose all other languages will have the same.
P.S. I personally think that answer is (x < 0...
Started by Nikolay Vyahhi on
, 13 posts
by 13 people.
Answer Snippets (Read the full thread at stackoverflow):
However, for (x < 0, memory architecture....
Time int x = -1; for (int i = 0; i < ONE_JILLION; i++) { int dummy = (x < 0); // Poof! Dummy have a comparison ( cmp ) and a conditional jump ( jCC ) instructions.
|
|
If x^2+y^2=1, is x+y=1 ?
(1) xy=0
(2) y=0 E
Last edited by Bunuel on Thu May 17, 2012 1:19 am, edited 1 time in total. Edited the OA
Started by Bunuel on
, 15 posts
by 8 people.
Answer Snippets (Read the full thread at gmatclub):
(1) xy=0 --> either x=0 or y=0 :
if x=0 , then x^2+y^2=y^2=1 and y=1 or y=-1 , ....
|
Ask your Facebook Friends
|
In IE, "x".split(/(x)/).length returns 0
In Firefox, Chrome, Safari, and Opera, it returns 3 .
Does anybody know the reason why? If possible, a reference link will be greatly appreciated.
I believe that it is a IE regex implementation issue, but I can...
Started by S.Mark on
, 3 posts
by 3 people.
Answer Snippets (Read the full thread at stackoverflow):
So for
"foo".split(/o/)
IE gives
[f]
where the other....
IE both ignores empty values and capture blocks within regular expressions .
Here for example http://blog.stchur.com/2007/03/28/split-broken-in-ie/
You're correct that there are implementation issues .
|
|
I know- Premature optimization.
But I've got code that's supposed to find out if a position is changed vs a cached position.
Current code is:
if(abs(newpos-oldpos) > 1){ }
Is it more efficient to use the following?
if(abs(newpos-oldpos) != 0){ .......
Started by Luciano on
, 13 posts
by 13 people.
Answer Snippets (Read the full thread at stackoverflow):
Instead;math.h> int t_gt(int x) { 0: 89 f8 mov %edi,%eax 2: c1 f8 1f sar $0x1f,%eax 5: 31 c7 xor %eax,%edi 7 test %edi,%....
x > 1 is not the same as x != 0.
I am missing something, they do not do the same thing .
|
|
Find lim([e^x sinx -(x+x^2)]/x^3) when x Approaching to 0?
Started by hero on
, 2 posts
by 2 people.
Answer Snippets (Read the full thread at yahoo):
0)=e^xsinx+e^xcosx-((1+2x).x^3-(x+x^2)3x…
when x approaches 0....
Use L'Hospital's rule and differentiate
lim(x approaching 0) (e^xsinx-(x+x^2)/x^3
f'(x)(x approach.
|
|
I'm trying to come up with a function, such that:
f(x) = 0, if x<0,
1, if x>=0
I feel I'm getting somewhere when I use:
f(x) = (-(x)+|x|)/2
With this, a negative number becomes its positive counterpart. And any number >= 0 equals 0. But I can...
Started by Le Master on
, 8 posts
by 3 people.
Answer Snippets (Read the full thread at mymathforum):
Other than a piecewise defined function, I don't think.
It's important that x can be equal to 0.
|
|
Int main(void){ float x =1; float y =2; while (x<y){ x = x +1 ; y = y +1; } printf("x is %d\n", x); printf("y is %d\n", y); }
I would expect x and y to increase to the point we run out of bits, but it seems like x and y is alway 0 in this case...
Answer Snippets (Read the full thread at stackoverflow):
Http://www.cplusplus.com/reference/clibrary/cstdio/printf/
Use %f for floats:
printf("x is %f\n", x); printf....
Y); // Output: x=0 y=1073741824
Most compilers can warn you about these types of errors if you set is for an integer.
|
|
Given a string of length N, how many ways are there of splitting it into X substrings (where X>0)?
Started by tomdee on
, 5 posts
by 5 people.
Answer Snippets (Read the full thread at stackoverflow):
X > N --> 0 partitions(N,X) --> Σ (I,0,N-X) λ partitions(N-I,X-1)
Now go finish yourAs many as there are combinations of X numbers that sum up to N ;)
Well, there are N-1 places of substrings X is one....
|
|
If f(x,y)+f(y,x)=0 for any x,y, is it true that f(x,y) can always be written as g(x)-g(y)?
If so, how to prove it?
Started by AlonsoMcLaren on
, 3 posts
by 2 people.
Answer Snippets (Read the full thread at physicsforums):
Thanks.
Regards.
For example yg(x)-xg(y) also satisfies the relation.
|
