|
The code below compiles, but has different behavior for the char type than for the int types.
In particular
cout << getIsTrue< isX<int8>::ikIsX >() << endl; cout << getIsTrue< isX<uint8>::ikIsX >() << endl...
Answer Snippets (Read the full thread at stackoverflow):
It probably would have been nice if char was just a synonym for either signed char or unsigned char depending on your compilers from the ....
That's correct, char, unsigned char and signed char are separate types.
|
|
I assume when I do char* = "string" its the same thing as char* = new char[6] . I believe these strings are created on the heap instead of the stack. So do I need to destroy them or free their memory when I'm done using them or do they get destroyed by...
Started by Daud on
, 7 posts
by 7 people.
Answer Snippets (Read the full thread at stackoverflow):
I assume when I do char* = "string" its the same thing as char* = new char[6....
Should read:
const char* c = "string";
And a new char array should be delete d just like any other need to delete [] your second example.
|
|
Yo!
I'm trying to copy a few chars from a char[] to a char*. I just want the chars from index 6 to (message length - 9).
Maybe the code example will explain my problem more:
char buffer[512] = "GET /testfile.htm HTTP/1.0"; char* filename; // I want *filename...
Started by petsson on
, 6 posts
by 6 people.
Answer Snippets (Read the full thread at stackoverflow):
char buffer[512] = "GET /testfile.htm HTTP/1.0"; char filename[512]; ....
The next problem is your offset.
Either just declare
char filename[512];
or malloc some memory for the new name (and don't a buffer for filename .
At anything.
|
Ask your Facebook Friends
|
Hi all,
I'm a beginner in C++ Programming language. I wanted to write a program that take the alphabets in a string array called str, and copy it in a new array called str_alpha.
And the same goes to numbers, the program copies it from str array to str...
Started by rafael on
, 6 posts
by 6 people.
Answer Snippets (Read the full thread at stackoverflow):
The do not use char* and the likes; use C++ predefined; for (unsigned int i = 0; i < str.length(); ++i) { char chr = str[i]; if (isalpha(chr)) alpha.push, used to copy strings , not individual....
I'm a beginner in C++ Programming language.
|
|
Someone here recently pointed out to me in a piece of code of mine I am using
char* name = malloc(256*sizeof(char)); // more code free(name);
I was under the impression that this way of setting up an array was identical to using
char name[256];
and that...
Started by faceless1_14 on
, 7 posts
by 7 people.
Answer Snippets (Read the full thread at stackoverflow):
It's useful to recall the whole "declared....
}
I was rather surprised in answers.
Also, sizeof(char) is always 1 according,
// file foo.c char name[256]; int foo() { // do something here.
Running out of stack or doing heavily recursive stuff.
|
|
I was interviewed recently and asked to write mystrcat(*s1, *s2, *s3) where s1 and s2 are source string and the concatenated results are given by s3 . I was told, don't worry about memory allocation of s3 and assume s1 and s2 are not null / invalid strings...
Started by curiousone on
, 8 posts
by 8 people.
Answer Snippets (Read the full thread at stackoverflow):
Then you basically....
) || (!s3)) return;
Here would be my comments
Both s1 and s2 should be typed to const char* since you have been:
void mystrcat(char *s1, char *s2, char *s3) { ASSERT( s1 ); ASSERT( s2 ); ASSERT( s3 ); ....
|
|
I have a old program in which some library function is used and i dont have that library.
So I am writing that program using libraries of c++. In that old code some function is there which is called like this
*string = newstrdup("Some string goes here...
Started by Chaithra on
, 6 posts
by 6 people.
Answer Snippets (Read the full thread at stackoverflow):
In a different way:
int redup(char **s1, const char *s2) { size_t len, size; if (s2 == NULL) return -1; len strdup :
char * newstrdup(char const* str) { char *c = new char[std::strlen(str) + 1]; std::strcpy(c....
|
|
Is there a function in c that will return the index of a char in a char array?
For example something like:
char values[] = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ"; char find = 'E'; int index = findInedexOf( values, find );
Started by Josh Curren on
, 7 posts
by 7 people.
Answer Snippets (Read the full thread at stackoverflow):
For example:
char values[] = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ"; char find = 'E'; const char *ptr = strchr(values, find); if(ptr) { int index = ptr - values; // do) from the original char....
The offset with the starting pointer.
|
|
How can I convert a char to a char* in c#?
I'm initializeing a String object like this:
String test=new String('c');
and I'm getting this error:
Argument '1': cannot convert from 'char' to 'char*'
Started by Uince on
, 15 posts
by 15 people.
Answer Snippets (Read the full thread at stackoverflow):
You can simply use:
String test="c";
If you have a specific need to convert a char variable character, you can use the following:
String test = new String(new char[] { 'c' });
string myString1 = new string(new char....
To store in it.
|
|
How can I convert an std::string to a char* or a const char*?
Answer Snippets (Read the full thread at stackoverflow):
You can use &mystring[0] to get a char * pointer::string to a function that needs const char* you can use
std::string str; const char * c = str.c_str();
If you want to get a writable....
Use the .c_str() method for const char *.
|
