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Blackberry Curve 3G-9300 also known as Curve 3 Now available for immediate sale and dispatch here in Nigeria, free delivery to any part of Nigeria. Same day delivery in Lagos, 24 hour delivery any other part of Nigeria. Prices from N58k each Brand new...
Started by omafones on
, 16 posts
by 7 people.
Answer Snippets (Read the full thread at nairaland):
Between the curve 3 and curve 2? Do they really look different? The Blackberry Curve 3G 9300 (Curve 3) looks exactly like the Blackberry Curve 8520 (Curve 2), the only difference? the Curve 3 has 3G them....
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Having searched the web, I see various people in various forums alluding to approximating a cubic curve with a quadratic one. But I can't find the formula.
What I want is this:
input: startX, startY, control1X, control1Y, control2X, control2Y, endX, endY...
Started by grumblebee on
, 5 posts
by 5 people.
Answer Snippets (Read the full thread at stackoverflow):
There is a good article discussing the problem, and a number of ways to solve to be an approximation... .
I would probably draw a series of curves instead of trying to draw one curve using a different alg with a single quadratic curve.
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I have the X,Y of 2 end points and 1 bezier point, of a Quadratic Bezier curve.
Using this data, how can I derive the polynomial representation of the curve?
Started by Jeremy Rudd on
, 4 posts
by 4 people.
Answer Snippets (Read the full thread at stackoverflow):
You could technically figure out how to eliminate "t" and get an equation in x and y, but it would not... .
Beziers are parametrized curves, namely:
x = f(t) y = g(t)
where t=0 yields one endpoint and t=1 yields the other.
That would be tricky.
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Ask your Facebook Friends
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You will understand what I mean if you use graphic editing programs like Gimp or Photoshop. To edit a curve on those programs (which probably is Bezier Curve), we can click on the curve, drag the mouse and the curve is changed accordingly. I suspect all...
Answer Snippets (Read the full thread at stackoverflow):
EDIT - In response to your question edit
In order....
Dragging simply changes the control points of the Bezier curve, and the curve is recalculated it?
Normally you manipulate the control points that is used to generate the bezier curve.
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It appears to me that the DC 's only support for curves of any sort is with splines. Are there any libraries that add bezier functionality, or is there a way to convert a bezier curve into a spline?
Started by Bibendum on
, 3 posts
by 3 people.
Answer Snippets (Read the full thread at stackoverflow):
Once you calculate a set of points on the curve, you could use DC.DrawLines to draw.
Given 4 control points, the formula for the associated cubic Bezier curve is not hard to compute .
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Is it possible to bring curve edges to divs using html and css only...without using images.
Started by Sumit M Asok on
, 5 posts
by 5 people.
Answer Snippets (Read the full thread at stackoverflow):
In CSS 3, you....
Not in a way that's compatible cross browser (in particular, IE does not yet support it) .
See this article for an example.
Yes, it is possible, but it is a CSS 3 feature that may not work on all browsers (or not the same in all browsers) .
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Im trying to implement a bezier curve and line segment intersection test. The closest thing my searching has turned up is to take the bezier curve (lets limit it to three control points for simplicity) find the mathematical function generating that curve...
Started by mizipzor on
, 3 posts
by 3 people.
Answer Snippets (Read the full thread at stackoverflow):
Three control points) can be expressed as: F(t) = A(1 .
A quadratic Bezier curve (i.e.
A Bezier curve is a parametric function.
It's fairly well explained in the Wikipedia article in several forms .
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I have a polyline that approximates a curve, and I want to draw it as a smooth curve in PostScript, which supports Bezier curve drawing. To do that, I need to generate two control points between each pair of polyline points. (I can't get the original ...
Started by xan on
, 3 posts
by 3 people.
Answer Snippets (Read the full thread at stackoverflow):
The equations are really simple but for those who don't want to repeat .
Segment smooth curve.
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I have a huge set of N-dimensional points (tens of millions; N is close to 100).
I need to map these points to a single dimension while preserving spatial locality. I want to use Hilbert space-filling curve to do it.
For each point I want to pick the ...
Started by Alexander Gladysh on
, 4 posts
by 4 people.
Answer Snippets (Read the full thread at stackoverflow):
However, this is a hard problem, and given.
I see what you meant by the Hilbert Curve approach now.
If you are interested in mapping.
I don't see how you can use a Hilbert curve in one dimension.
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I am attended to develop with framework.
so, I'm Very confused, about which easier in learning curve to start develop with..
that I need to develop a project using a framework as soon as possible.
Started by assaqqaf on
, 6 posts
by 6 people.
Answer Snippets (Read the full thread at stackoverflow):
The documentation.
For more info see:
CodeIgniter vs Zend Framework
CodeIgniter defiantly has a smaller learning curve.
I think CodeIgniter has lesser learning curve and provides great documentation too.
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