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I have an xml file <Abc> <image filename="1.jpg" heading="1.jpg" /> <image filename="10.jpg" heading="10.jpg" /> <image filename="11.jpg" heading="11.jpg" /> <image filename="2.jpg" heading="2.jpg" /> <image filename="...
Started by on , 4 posts by 4 people.  
Or to keep the attributes on the root: XmlNode lastChild; while((lastChild = root.LastChild"); doc.DocumentElement.RemoveAll(); string result = doc.OuterXml; But if you know the root node name.
Hello Good day. As i know. There is a root element in XML file. But from the XSD file structure, it is not easy to get the root element value. Is there any method to do it? (I wouldn't like to take use of hard code to find XSD root element value in my...
Started by on , 3 posts by 3 people.  
If you only genuinely want a single type to be valid as a root element XmlElement schemaElement....
Whilst a single document can only contain one root element, as XSD can actually define multiple valid root elements .
I was wondering if it's possible to write something like this: <Window ... xmlns definitions ... DataContext=<!--Create an instance here--> ></Window> Instead of this: <Window ... xmlns definitions ... > <Window.DataContext&...
Started by on , 3 posts by 3 people.  
I am not sure if x:Static caches the object it once retrieved... .
How about DataContext="{x:Static SomeClass.SomeProperty}" and then in SomeClass: public static object SomeProperty { get { return new object(); } } Where object is the type you want to create .
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How to add a comment node before the root <svg> element but after the xml prolog? Or will it be less resource expensive to insert the comment with a regexp on the serialized DOM?
Started by on , 3 posts by 3 people.  
R="30" style="fill: none; stroke: #F00; stroke-width: 2px"/> </svg> The root element (ie DOMParser().parseFromString(s, 'text/xml'); // insert a comment node before the root node.
Hi, can i someway disable rendering of root element of collection? this class with serialization attibutes [XmlRoot(ElementName="SHOPITEM", Namespace="")] public class ShopItem { [XmlElement("PRODUCTNAME")] public string ProductName { get; set; } [XmlArrayItem...
Started by on , 4 posts by 4 people.  
What you can do however, is manuallyI don't believe it is possible to remove this element using the default xml serialization" element, just mark it up with an [XmlElement....
Xml (no root element) for the object, which is not allowed.
I need to create an XmlDocument with a root element containing multiple namespaces. Am using C# 2.0 or 3.0 Here is my code: XmlDocument doc = new XmlDocument(); XmlElement root = doc.CreateElement("JOBS", "http://www.example.com"); doc.AppendChild(root...
Started by on , 4 posts by 4 people.  
Hi, try to add the namespace attribute to the root element: XmlDocument doc = new XmlDocument(); XmlElement root = doc.CreateElement("JOBS", "http://www.example.com"); root.SetAttribute("xmlns:JOB", "http://www.example.com"); doc.....
I need to be able to select the root element without knowing the node types, class, id or hierachy. <div id="0"> <div id="0a"> <div id="a01"></div> </div> <div id="0b"> </div> <div id="0c"> </div> ...
Started by on , 6 posts by 6 people.  
Var root = document.firstChild; you could look into using the parent is that for a html document, this will always give....
If you're looking for a root div element (presuming is not needed...
Gt; * > *'); and so on and so forth.
Hi all, I'm interested in assigning the tag name of the root element in an xml document to an xslt variable. For instance, if the document looked like (minus the DTD): <foo xmlns="http:// "> <bar>1</bar> </foo> and I wanted to ...
Started by on , 5 posts by 5 people.  
One XPath expression to obtain the name of the top (not root!) element is: name(/*) The name to retrieve the name of the outermost....
See http.
The root node has no name.
Instructions that precede or follow the outermost element).
Hi All, I am writing a PowerShell wrapper for an existing Perl script. The Perl script is fed a couple of parameters and goes off and configures all our HP iLO devices for us, and returns the results in an XML format. The problem is the result comes out...
Started by on , 3 posts by 3 people.  
I think VERSION="2.22"/> is a self-closing....
You could also split that a root element would work since each of those bits have a version node in there.
Either tweaking the Perl or wrapping a root element around it should work.
I am using lxml to manipulate some existing XML documents, and I want to introduce as little diff noise as possible. Unfortunately by default lxml.etree.XMLParser doesn't preserve whitespace before or after the root element of a document: >>>...
Started by on , 3 posts by 3 people.  
Tail = re.findall(r"^\s*|\s*$", xml)[:2] >>> root = etree.fromstring(xml) >>> out = head + etree.tostring(root) + tail >>> out == xml True.
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