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I used to code in php4 but now I switched to php5 and the following code throws the below exception. Why is that? CODE: $mysqli = new mysqli($CONFIG_DB_HOST,$CONFIG_DB_USERNAME,$CONFIG_DB_PASSWORD,$CONFIG_DB_NAME); $result = $mysqli->query("select ...
Started by on , 4 posts by 4 people.  
Also always check the return value of the query() method before you proceed: if (!$mysqli->query("query")) { printf("Error: %s\n", $mysqli->error); } You can also check to see if your;?php if ($result = $mysqli->....
You get.
Hi, I am trying to get my head around mysql. Can someone tell my why this mysql query is not working? I am getting the following error: Warning: mysqli_error() expects exactly 1 parameter, 0 given in /home/freebet2/public_html/test.php on line 11 test...
Started by on , 4 posts by 4 people.  
You are mixing the object-oriented and the procedural styles of the mysqli API : You are using object-oriented : $result = new mysqli....
Use mysqli_error($result) as mysqli_error expects the connection to be passed as a parameter.
I want to be able to make classes which extend the MySQLi class to perform all its SQL queries. $mysql = new mysqli('localhost', 'root', 'password', 'database') or die('error connecting to the database'); I dont know how to do this without globalising...
Started by on , 6 posts by 6 people.  
() ) { throw new exception(mysqli_connect_error(), mysqli_connect_errno()); } } public static function Blog extends mysqli { public function __construct($host, $user, $password, $database) { parent, $password, $database) { ....
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I've combined this topic with my earlier topic MySQLi Connection and Statement Classes and separated out the classes to make life easier for you. The documentation is reasonably long so rather than provide it here you can see it here: MySQLi Classes ....
Started by on , 15 posts by 5 people.  
Email Address....
Email Address Validation :: MySQLi Classes :: Password Validator The way that works in Zend Christopher 's issue).
Email Address Validation :: MySQLi Classes :: Password Validator I'm) accordingly.
:43 pm, edited 1 time in total.
Can someone tell me what I'm doing wrong? I cannot get the affected rows returned after a row has been deleted. The function always returns int(0) even though the delete action was preformed. I read where I needed to clear or close the results which I...
Started by on , 3 posts by 3 people.  
You'll need to select the number of rows affected in the stored procedure then have your stored procedure return the rows affected via... .
When calling a stored procedure or function the int(0) is noting that the stored procedure exited without any errors .
Options -> performance -> Jquery Source When i try to change the source from Google Ajax API CDN to any other i get this error. An exception occurred: Mysqli prepare error: MySQL server has gone away in \library\Zend\Db\Statement\Mysqli.php on line...
Started by on , 11 posts by 3 people.  
Answer Snippets (Read the full thread at xenforo):
Thanks Jake for your reply but unfortunately....
That error is caused by one of these MySQL settings being exceeded: wait_timeout max_allowed_packet If you don't manage your own server then you need to ask your host or server person to increase these settings .
On Thu, 02 Jul 2009 09:12:25 -0400, Jerry Stuckle <jstucklex@attglobal.net That's strange, Paolo. Obviously, something has changed (although I do believe you when you say you didn't do anything). I guess the first thing would be to see if MySQL...
Started by on , 22 posts by 5 people.  
Answer Snippets (Read the full thread at omgili):
The 'undefined function' means the script doesn't have access to mysqli....
"); } if (! mysqli_num_rows($rs)) { throw new Exception("Il widget specificato non esiste"); } $data launching mysqli_connect() function.
[Edit] Klassen-Beschreibung im 2. Post begonnen Kleinen Fehler in der Methode registerUser behoben, der dazu führte, dass neue User im mit isActive=0 registriert wurden, auch wenn durch Übergabe des Parameters $requiresActivation=false festgelegt wurde...
Started by on , 4 posts by 2 people.  
Im Einzelnen sind dies: const activationExpires....
Konstanten In den Konstanten werden einige Einstellungen für Registrierung und Login festgelegt .
Die restlichen Methoden folgen noch.
Da ich gerade etwas Zeit hatte, mal noch eine Beschreibung der Klasse .
I'm trying to use exceptions in PHP as a way of avoiding multiple if-then-else blocks. However, when I try to catch the exception, I get the error Parse error: syntax error, unexpected T_CATCH in /directory/functions.php on line 66 . Am I doing something...
Started by on , 5 posts by 5 people.  
DbConnection,$query1); if ($sDivisionIdArray==false){throw new Exception ();} $sDisplayQueryArray = mysqli; $sDivisionIdArray = mysqli_query($dbConnection,$query1); if ($sDivisionIdArray == false) throw new Exception,$query....
I was wondering how do I update two tables using mysql and php? How would I add the second table to the code? Here is the code below. $dbc = mysqli_query($mysqli,"UPDATE tags SET count='$tag_info_count' WHERE id='$tag_info_id'")
Started by on , 3 posts by 3 people.  
I forget the transaction syntax for mysqli, but basically try { mysql } catch (Exception E) { msyql_rollback_transaction(); // not correct syntax } check out Execute.
You create a transaction.
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