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Hi I heard most elegant property of java is Garbage Collection I wanna know does it guarantee that a program will not run out of memory?
Started by on , 13 posts by 13 people.  
It will not even guarantee that....
No, garbage collection cannot guarantee that your application will not run out of memory.
It is perfectly possible for a programmer to mistakingly create for recycling .
No it does not guarantee this.
Using C or C++, After I decrypt a file to disk- how can I guarantee it is deleted if the application crashes or the system powers off and can't clean it up properly? Using C or C++, on Windows and Linux?
Started by on , 14 posts by 14 people.  
And it may be possible.
If the user unplugs the computer you can't guarantee that the file will be deleted.
I am using a linkedHashMap to guarantee order when someone tries to access it. However, when it comes time to iterate over it, does using entrySet() to return key/value pairs guarantee order as well? No changes will be made while iterating. EDIT: Also...
Started by on , 4 posts by 4 people.  
(A key k is reinserted into a map ....
Note that insertion order is not affected if a key is re-inserted into the map .
This linked list defines the iteration ordering, which is normally the order in which keys were inserted into the map (insertion-order) .
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When a file is closed using close() or fclose() (for example), does Linux guarantee that the file is written back to (persistent) disc? What I mean is, if close() returns 0 and then immediately afterwards the power fails, are previously written data guaranteed...
Started by on , 8 posts by 8 people.  
From " man 2 close....
I don't think Linux can guarantee this since the drive itself can cache data too.
There is some controversy in the Linux kernel world because even fsync doesn't guarantee and the disk never knows the file was there.
I have code that controls a mutex lock/unlock based on scope: void PerformLogin() { ScopeLock < Lock > LoginLock( &m_LoginLock ); doLoginCommand(); ScopeLock < SharedMemoryBase > MemoryLock( &m_SharedMemory ); doStoreLogin(); ... } Can I guarantee...
Started by on , 5 posts by 5 people.  
Hence you could not guarantee t2's destructor.
} If C++ did not guarantee for t1 to be destroyed before t2's destructor ran.
Consider void Foo() { Type1 t1; Type2 t2(&t1); ...
On the stack.
In Java, I use if (a != null && a.fun()); by taking full advantage of short-circuit evaluation and expression are evaluated from left to right? In C++, can I do the same? Are they guarantee to portable across different platform and compiler? if (a != ...
Started by on , 3 posts by 3 people.  
See also: http://stackoverflow.com/questions/628526/is-short-circuiting-boolean-operators-mandated-in-c-c-and-evaluation-order Yes, it is guaranteed for the "built....
&& and || short circuit in C and C++; it is guaranteed by the standard.
Say I have 3 strings in a List (e.g. "1","2","3"). Then i want to reorder them to place "2" in position 1 (e.g. "2","1","3"). I am using this code (setting indexToMoveTo to 1): listInstance.Remove(itemToMove); listInstance.Insert(indexToMoveTo, itemToMove...
Started by on , 6 posts by 6 people.  
The List<> class does guarantee ordering - things will be retained in the list in the order; guarantee that items will be returned in the order they were added? Here's 4 items, with their index.
I was stuck at one question in an interview. Given two threads, and each one has a lock, how to guarantee no deadlock. My knowledge is that it is not easy to avoid deadlock, that's why I got stuck. Can anybody give a hint. Thanks!
Started by on , 7 posts by 7 people.  
With a single lock it's not possible to get....
The description is a bit lacking, but if you impose a locking order (e.g, if the locks are A and B, never lock B unless you already locked A, and never release A while B is locked), then deadlock won't occur .
There's a few questions on stack overflow on this topic but I'm still unclear: I know the flash engine is single threaded so when it receives an event, does it essentially break off, execute any registered event listeners (in no guaranteed order) then...
Started by on , 4 posts by 4 people.  
Meaning.
Yes, you can guarantee both assertions in this exact situation.
One of your events.
Does a List<T> always guarantee that items will be returned in the order they were added when enumerated? Updated : Thanks for all the answers folks, puts my mind at ease. I had a quick poke around the List<T> class with .NET Reflector (should...
Started by on , 4 posts by 4 people.  
You can insert items at a certain index so the next items will move one position.... .
The List is index based and new items will always be added to the end of the list .
But it's not part of the specification.
Yes according to this MSDN Forum thread Yes.
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