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I am trying to write an algorithm to calculate outcomes. But I need help with combinatorics.
Suppose I have to choose 2 numbers from 1 to 10. From the fundamental rule of counting, in the absence of any restriction, the number of possible outcomes is ...
Started by blackgeneral on
, 3 posts
by 3 people.
Answer Snippets (Read the full thread at stackoverflow):
Imagine your grid ....
+ 2 + 1 = 45
This is called an arithmetic progression the sum is equal to:
f(n) = n * (n+1) / 2 = 9 * 10 / 2 = 45
45 .
9: 10 = 1 possibility So
9 + 8 + .. .
If you choose:
1: 2 to 10 = 9 possibilities 2: 3 to 10 = 8 possibilities .. .
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Number n = new Number(5) is illegal, but Number n = 5 isn't. Why?
Answer Snippets (Read the full thread at stackoverflow):
Fundamentally, it's because Number is an abstract class - there is no constructor that corresponds to Number(5) , and even if there was you still would not be able creating an Integer object* - which,....
And Integer is a Number .
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Hi
I have this number: 1234.5678 (as a text)
I need this number as double, with only 2 numbers after the dot
But without Round the number
in 1234.5678 - i get 1234.57
in 12.8 - i get 12.90
How I can do it ?
Started by Gold on
, 8 posts
by 8 people.
Answer Snippets (Read the full thread at stackoverflow):
This is because you can't.
Multiply by 100, take floor() of the number, divide by 100 again.
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Ask your Facebook Friends
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In javascript how to convert sequence of numbers in an array to range of numbers?
eg. [2,3,4,5,10,18,19,20] to [2-5,10,18-20]
Started by gokul on
, 8 posts
by 8 people.
Answer Snippets (Read the full thread at stackoverflow):
So have a:
struct range { int start; int end; } range;
where if array[i+1] == array[i]+1; (where i is the currently observed number_number ....
The numbers and see if the next number is 1 bigger then the current number.
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I have a list of constant numbers. I need find the closest number to x, in the list of the numbers.
Any ideas on how to implement this alogrithm?
Thank You.
Started by Alon on
, 8 posts
by 8 people.
Answer Snippets (Read the full thread at stackoverflow):
Each search....
It can be done using SortedList :
Blog post on finding closest number to query it for the closest number then the best choice is to use List and use naive algorithm to query it for the closest number.
And its neighbors.
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As the title says What is the difference between a randomly generated number and secure randomly generated number?
Started by Shoban on
, 9 posts
by 9 people.
Answer Snippets (Read the full thread at stackoverflow):
Because it's a pseudo random number....
With just a "random number" one usually means a pseudo random number.
Example: a linear feedback shift register produces lots of random predicted .
For a secure random number generator.
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Multiplying two binary numbers takes n^2 time, yet squaring a number can be done more efficiently somehow. (with n being the number of bits) How could that be?
Or is it not possible? This is insanity!
Started by Jess on
, 13 posts
by 13 people.
Answer Snippets (Read the full thread at stackoverflow):
The number of multiplication operations....
To multiply is even.
Do you mean multiplying a number by a power number is a power of two everything is totally simple once you know the power.
I don't believe either of your assertions are true.
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I need a program to convert Binary numbers into Decimal number in Java or in C++.
is there some one who can help me.
Started by Gowtham on
, 5 posts
by 5 people.
Answer Snippets (Read the full thread at stackoverflow):
The first element i.e..
2.) Store the number in an array.
:
1.) Prompt the user for a binary number.
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I'm working through the process of installing CruiseControl.net and converting an Msbuild script to work with it. I'd like our build number to reflect the Subversion revision number. It appears as though the LastChangeLabeller should work, but all I get...
Started by Rick on
, 5 posts
by 5 people.
Answer Snippets (Read the full thread at stackoverflow):
I modified the code slightly because I wanted the subversion revision number to be last number in the version number....
The build number in CC.Net, I believe you want to use a labeller block - possibly a Last Change solution for me.
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Problem I need to create 32 Bit numbers (signed or unsigned doesn't matter, the highest bit will never be set anyway) and each number must have a given number of Bits set.
Naive Solution The easiest solution is of course to start with the number of zero...
Started by Mecki on
, 5 posts
by 5 people.
Answer Snippets (Read the full thread at stackoverflow):
Go back to increasing the....
Then increase the penultimate number, and set the last number to one higher: [0,1,3,4].
And then increase the last number each time (getting [0,1,2,4], [0,1,2,5] ...) until you hit the limit [0,1,2,31].
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