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Consider the following scenario:
We have a number of sequential building blocks (e.g. 12 building blocks , ordered from 1 to 12), distributed randomly (but not necessarily equally) on a number of builders (e.g. 3 builders ). The builders are required ...
Started by Noor on
, 5 posts
by 4 people.
Answer Snippets (Read the full thread at stackoverflow):
Have Pi(x in {x,y}) express the probability that player i choose x when facing a choice between x.
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On Mon, 8 Jun 2009 15:58:58 +0200, "Johan" <johan.lyhagen@dis.uu.se
Hi,
I have the following problem.
I know the value of Spearman correlation, s, and know that for a sample size
n it is related to Pearson correlation, r by:
s = (6/(pi(n+1))...
Started by Johan on
, 5 posts
by 3 people.
Answer Snippets (Read the full thread at omgili):
What is pi(n+1) ?
also use * for the multiply sign" <johan.lyhagen@dis.uu.se
Ok, sorry for that:
n is integer
pi = 4*arctan(1)
We know that r is bounded, -1=< r =<....
Johan.lyhagen@dis.uu.senews:4a2d1922$1@alca.its.uu.se...
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TRIGO SOLVING HELP!!? Hi, I think I know how to attempt this question, but I realized that I was unable to factorize! Please help, would appreciate it so much!
Use factor theorem to factorise 6c^3-19c^2+c+6=0
therefore solve 6cos^3x-19cos^2x+cosx+6=0 ...
Started by Yu on
, 1 posts
by 1 people.
Answer Snippets (Read the full thread at yahoo):
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Started by babymagus on
, 15 posts
by 3 people.
Answer Snippets (Read the full thread at vr-zone):
Pc????As low as $30 to Solving Your Pc(Desktop) and Network(SCV or ADSL) Problems
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Hi, I think I know how to attempt this question, but I realized that I was unable to factorize! Please help, would appreciate it so much!
Use factor theorem to factorise 6c^3-19c^2+c+6=0
therefore solve 6cos^3x-19cos^2x+cosx+6=0 for 0≤x≤pi
Just checking...
Started by chocolate on
, 2 posts
by 2 people.
Answer Snippets (Read the full thread at mymathforum):
Thus....
Thus is not a factor.
To factor the given polynomial:
I would use the rational roots theorem, which states that if has rational roots, it will come from the list:
I like integers, so beginning with the positives, let's check:
thus is not a factor .
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I am stuck on this one.
csc^2 = 2cot + 4
I did the pythagorean identity and my equation becomes
1 + cot^2 = 2cot + 4 and ended up at
(cot - 3) (cot +1)=0
I think part of my answer is 2pik + 3pi/4, or is it pi k + 3pi/4? and 5pi/4? But what about cot=3...
Started by outermeasure on
, 3 posts
by 3 people.
Answer Snippets (Read the full thread at sosmath):
Pi/4, or is it pi k + 3pi/4? and 5pi/4? But what about cot=3?
Cotangent is 1 at , the only one.
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On Sat, 1 Aug 2009 15:45:28 -0700 (PDT), Nando <nando.portugal@gmail.com
Hy,
I'm solving this exercise where I'm suppose to do something like this
(I'm sorry if this is too obvious, but it wasn't to me):
sin(x) + cox(x)i = sin (pi/2 + x) + cos...
Started by Nando on
, 9 posts
by 6 people.
Answer Snippets (Read the full thread at omgili):
Camera http://www.....
Estimate of function
with CIs (GPS) ...
Sin(-x) = -sin(x) and cos(-x) = cos(x)
1024(2cos(pi/33(x)~list(~sin
(2*pi*x)+cos(2*pi*x)-1,lspline(x,type="sine0" ...
= 1024(cos(-pi/
3)+cos(pi/3) + i (sin(-pi ...
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On Wed, 14 Oct 2009 19:06:32 -0700 (PDT), Mapsread <cw_chw@yahoo.com
Greetings,
I'm trying to teach myself contour integration/complex analysis and
finding it a little more challenging than I expected. To make a long
story short, it's not obvious...
Started by Mapsread on
, 5 posts
by 2 people.
Answer Snippets (Read the full thread at omgili):
Thus, the
integral from t=w to t = pi-w has magnitude <= R*exp(-rRc)/R * (pi-2w)
= (pi-2w)*exp(-rRc), so goes to t=w is <= R*w/R = w; and similarly....
So for any small w <= t <= pi-w, so |integrand} <= exp(-rcR)/R for such w.
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On Thu, 7 May 2009 11:47:01 +0000 (UTC), "Andrew Mackenzie" <#macac#001#@students.unisa.edu.au
I am trying to find the value of t, when phi = 60? or pi/3 radians.
syms t
x = 8 + 2 * cos(pi*t);
alpha = atan(8/x);
beta = acos(sqrt(x^2 + 64) / 40)...
Started by Andrew Mackenzie on
, 7 posts
by 4 people.
Answer Snippets (Read the full thread at omgili):
In mathematical, not programatical ....
Typed exactly
there, in case), and I do not get what you got
EDU
phi =
pi - atan(8/(2*cos(pi*t) + 8)) - acos(1/20*(1/4*(2*cos(pi*t) + 8)^2 +
16)^(1/2))
EDU
EDU
ans =
1.0000 - 1.1377i.
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On Thu, 15 Oct 2009 10:27:46 -0700 (PDT), Ray Vickson <rgvickson@gmail.com
On Oct 14, 7:06 pm, Mapsread <cw_...@yahoo.com
let f = exp(isr)/(s^2-k^2). On s = R*exp(i*t) we have f = exp(rRicos
(t))*exp(-rRsin(t))/D, where D = R^2*exp(i*2*t)-k^2...
Started by Ray Vickson on
, 4 posts
by 2 people.
Answer Snippets (Read the full thread at omgili):
Epsilon R0 large enough that |integral from w to pi - w| < epsilon/3 (because
sin(t) exponentially.
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