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Suppose p(x,r) is a polynomial, where r is a parameter. For each r, you could evaluate the roots of p. As r changes, the roots of p changes continuous. What is the theorem that proves this?
Example:
Started by Twinbee on
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by 3 people.
Answer Snippets (Read the full thread at artofproblemsolving):
Therefore, all roots of must from to through the interval....
Suppose is a root of , and is a root, the relation is impossible to hold, therefore it cannot be a root.
The roots of lies on a complex plane.
Differentiated.
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Find the roots of in and factor it.
Started by newsun on
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by 3 people.
Answer Snippets (Read the full thread at artofproblemsolving):
Do you know any information....
But your solution is completely wrong.
But your solution is completely wrong.
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I've been studying DDD for the past 2 weeks, and one of the things that really stuck out to me was how aggregate roots can contain other aggregate roots. Aggregate roots are retrieved from the repository, but if a root contains another root, does the ...
Started by Ed on
, 3 posts
by 3 people.
Answer Snippets (Read the full thread at stackoverflow):
The repository for this composite aggregate root does not require....
I have mappings for all my entities of which several are aggregate roots and one of these has several other aggregate roots as member variables.
I'm using - nHibernate.
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Any idea what would case the error The user <> does not have any roots specified; the channel is being closed when I login to an SFTP site.
Started by kjanz1899 on
, 3 posts
by 3 people.
Answer Snippets (Read the full thread at superuser):
Go figure!.
Check to see if the user has access rights to their "root the "user does not have any root specified message".
Seems like a permissions problem.
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I'm trying to use the Repository pattern for my current project and i'm currently in the process of trying to model the domain and find the aggregate roots.
I've read of the 'Cascading Delete' rule which states that if it doesn't make sense to delete ...
Started by Mathew on
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by 3 people.
Answer Snippets (Read the full thread at stackoverflow):
These references should.
An aggregate usually contains references to other aggregate roots.
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I'm having trouble calculating roots of rather large numbers using bc_math, example:
- pow(2, 2) // 4, power correct - pow(4, 0.5) // 2, square root correct - bcpow(2, 2) // 4, power correct - bcpow(4, 0.5) // 1, square root INCORRECT
Does anybody knows...
Started by Alix Axel on
, 3 posts
by 3 people.
Answer Snippets (Read the full thread at stackoverflow):
I did come across this discussion of a PHP N-th root.
That it doesn't support non-integer exponents.
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I'm struggling with aggregates and aggregate roots. I have a natural aggregate root which works for about 60% of the user requests. I.e. those requests naturally apply to the aggregate root.
Within my aggregate I have another entity which can only exist...
Started by ng5000 on
, 4 posts
by 4 people.
Answer Snippets (Read the full thread at stackoverflow):
In the case of a shopping cart with an cart and line items I have both of those as aggregate roots since aggregate root since I ....
The idea of an aggregate is to guarantee consistency, being the root responsible for data integrity.
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I want to ask for some advise on how to avoid writing objects which are mere data containers.
Consider the following Aggregate Root:
public class Post : IAggregateRoot { List<Comment> Comments {get; set;} }
Given the pinciples that govern how aggregate...
Started by Th3Fix3r on
, 3 posts
by 3 people.
Answer Snippets (Read the full thread at stackoverflow):
You've got the concept of aggregate roots correct, but your two options are really about.
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I tried to use the standard iterative algorithm to compute nth roots.
For instance (111^123)^(1/123).
The standard algorithm computes high powers of the base (in this case 111^123) which takes a lot of time. The algorithm is given here http://en.wikipedia...
Started by amit on
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by 3 people.
Answer Snippets (Read the full thread at stackoverflow):
111 * 111 = ....
Here is the whole sequence (Note that this is probably not the most efficient way) .
What I mean is do:
111 * 111 = 111^2, now you know what 111^2 is, you can now calculate 111^4 by doing (111^2) * (111^2) .
Try using binary exponentiation.
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I have a simple parent/child type view with two columns: MYID and MYPARENTID. In PL/SQL, getting a list of all of the children of a parent is simple enough:
SELECT MYID FROM MYVIEW START WITH MYID = 'TargetId1' CONNECT BY PRIOR MYID = MYPARENTID
And I...
Started by DivisionByZorro on
, 3 posts
by 3 people.
Answer Snippets (Read the full thread at stackoverflow):
SELECT MYID ,CONNECT_BY_ROOT MYID ROOT FROM MYVIEW START WITH MYID IN ('TargetId1', 'TargetId2', 'TargetId3') CONNECT BY PRIOR MYID.
Requires Oracle 10g, though.
BY_ROOT is what you are looking for.
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